Mr. Bouyer
Day 1 | Day 2 - 3 | Day 4 | Lab 1 | Lab 2 | Skills Test

  • Describe melting and boiling using vapor pressure.
  • Give examples of dynamic equilibrium using the physical states of matter.
  • Apply Le Chatelier's Principle to systems at equilibrium.
  • Describe molecular attraction at the surface of liquids.

Heat Changes In Matter

Explore this Internet Website about Chemistry Important concepts:

Lab #1 the key points to useful information on this page
Melting - Commonly used to indicate changing from solid to liquid.

Freezing - Changing from liquid to solid. Boiling - Commonly used to indicate changing from liquid to gas. Evaporation - Molecules leaving the surface of a liquid. Sublimation - When a substance changes directly from a solid to a gas. Vapor - The gaseous phase of a substance that is not a gas at room temperature.

Volatile - A liquid that readily evaporates at room temperature.

Equilibrium - When there is no net change in a system.

Dynamic equilibrium -

When a vapor is in equilibrium with its liquid as one molecule leaves the liquid to become a vapor, another molecule leaves the vapor to become a liquid. In other words, an equal number of molecules will be found moving in both directions.

How substances behave when changing phase is determined by intermolecular forces.

Here are two rules of thumb:

  1. Substances with low vapor pressures have strong intermolecular forces. Those with high vapor pressures have weak intermolecular forces. Ionic compounds do not exert a significant vapor pressure because the interionic forces are too strong to be overcome.
  2. Substances with weak intermolecular forces have lower melting points than substances with strong intermolecular forces.


Calculating the energy changes during phase change:  (chem lab 244)

Symbols used in heat calculations:

Enthalpy of fusion: formulas

Enthalpy of vaporization: formulas Heat transfer: formulas

Sample Heat Calculation Problem:

How much heat is needed to convert 250g of ice at -30 oC to steam at 150 oC?

This problem requires six individual calculations. There are three in which the phase does not change (yellow), two in which the phase changes (green), and a final calculation to solve the problem. (pink)
1. Raise the temperature of ice from -30 oC to 0 oC - no phase change

q = m DT Cp = (250g) (30 Co) (2.06 J/g . Co) = 15,450 J
2. Melt the ice - phase change occurs - temperature does not change

q = m DHfus = (250g) (334 J/g) = 83,500 J
3. Raise the temperature of liquid water from 0 oC to 100 oC - no phase change

q = m DT Cp = (250g) (100 Co) (4.18 J/g . Co) = 104,500 J
4. Vaporize the liquid water - phase change occurs - temperature does not change

q = m DHvap = (250g) (2260 J/g) = 565,000 J
5. Raise the temperature of the water vapor from 100 oC to 150 oC - no phase change

q = m DT Cp = (250g) (50 Co) (2.02 J/g . Co) = 25,250 J
6. Find the total heat needed for the conversion -

Add the q's from steps 1 - 5.       Total q = 793,700 J

  Lab #2 the key points to useful information on this page

Homework Assignment 201:
This assignment must be turned in by the beginning of class tomorrow to receive credit.
Scoring criteria
link to a local webpage

  1. Find the theoretical freezing point and boiling point temperatures of CO2.
  2. Work the following heat calculation practice problems:
    1. How much heat is needed to raise the temperature of a 50g piece of copper metal 10 Co?
    2. How much heat is needed to change 100g of lead from a solid to a liquid?
    3. How much heat must be removed to lower the temperature of one pound of water from 70 oC to 5 oC? How many BTU's is that?


Day 2 - 3

Molecular attraction at the surface of a liquid is not equal.
Arrows in the diagram below indicate molecular attraction on the water molecules.

In-class Assignment 203:
This assignment must be turned in by the end of class tomorrow to receive credit.

  1. Use this planning guidelink to a local webpage to write an essay about the formation of snowflakes.


Day 4 - Phase diagramslink to a local webpage

 

Research Links:

Chemistry Class X

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  1. q = m T Cp = (50g) (10 Co) ( .38 J/g . Co) = 190 J
  2. q = m Hfus = (100g) (23 J/g) = 2300 J